\(\int x (d-c^2 d x^2)^{3/2} (a+b \arcsin (c x))^n \, dx\) [488]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [F]
   Fricas [F]
   Sympy [F(-1)]
   Maxima [F]
   Giac [F(-2)]
   Mupad [F(-1)]

Optimal result

Integrand size = 27, antiderivative size = 595 \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=-\frac {d e^{-\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {d e^{\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {3^{-n} d e^{-\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {3^{-n} d e^{\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {5^{-1-n} d e^{-\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {5^{-1-n} d e^{\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}} \]

[Out]

-1/16*d*(a+b*arcsin(c*x))^n*GAMMA(1+n,-I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c^2/exp(I*a/b)/((-I*(a+b*ar
csin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-1/16*d*exp(I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,I*(a+b*arcsin(c*x))/b)*(-c
^2*d*x^2+d)^(1/2)/c^2/((I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-1/32*d*(a+b*arcsin(c*x))^n*GAMMA(1+n,-3*I
*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/(3^n)/c^2/exp(3*I*a/b)/((-I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1
/2)-1/32*d*exp(3*I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,3*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/(3^n)/c^2/
((I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-1/32*5^(-1-n)*d*(a+b*arcsin(c*x))^n*GAMMA(1+n,-5*I*(a+b*arcsin(
c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c^2/exp(5*I*a/b)/((-I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-1/32*5^(-1-n)*d
*exp(5*I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,5*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c^2/((I*(a+b*arcsin(
c*x))/b)^n)/(-c^2*x^2+1)^(1/2)

Rubi [A] (verified)

Time = 0.35 (sec) , antiderivative size = 595, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {4809, 4491, 3389, 2212} \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=-\frac {d e^{-\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,-\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {d 3^{-n} e^{-\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,-\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {d 5^{-n-1} e^{-\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,-\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {d e^{\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {d 3^{-n} e^{\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {d 5^{-n-1} e^{\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (n+1,\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}} \]

[In]

Int[x*(d - c^2*d*x^2)^(3/2)*(a + b*ArcSin[c*x])^n,x]

[Out]

-1/16*(d*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((-I)*(a + b*ArcSin[c*x]))/b])/(c^2*E^((I*a)/b
)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b*ArcSin[c*x]))/b)^n) - (d*E^((I*a)/b)*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])
^n*Gamma[1 + n, (I*(a + b*ArcSin[c*x]))/b])/(16*c^2*Sqrt[1 - c^2*x^2]*((I*(a + b*ArcSin[c*x]))/b)^n) - (d*Sqrt
[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((-3*I)*(a + b*ArcSin[c*x]))/b])/(32*3^n*c^2*E^(((3*I)*a)/b
)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b*ArcSin[c*x]))/b)^n) - (d*E^(((3*I)*a)/b)*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c
*x])^n*Gamma[1 + n, ((3*I)*(a + b*ArcSin[c*x]))/b])/(32*3^n*c^2*Sqrt[1 - c^2*x^2]*((I*(a + b*ArcSin[c*x]))/b)^
n) - (5^(-1 - n)*d*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((-5*I)*(a + b*ArcSin[c*x]))/b])/(32
*c^2*E^(((5*I)*a)/b)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b*ArcSin[c*x]))/b)^n) - (5^(-1 - n)*d*E^(((5*I)*a)/b)*Sqrt[
d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((5*I)*(a + b*ArcSin[c*x]))/b])/(32*c^2*Sqrt[1 - c^2*x^2]*((
I*(a + b*ArcSin[c*x]))/b)^n)

Rule 2212

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c
+ d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d))^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m
 + 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3389

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/E^(I*(e + f*x))
, x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e, f, m}, x]

Rule 4491

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[E
xpandTrigReduce[(c + d*x)^m, Sin[a + b*x]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0]
&& IGtQ[p, 0]

Rule 4809

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[(1/(b*c
^(m + 1)))*Simp[(d + e*x^2)^p/(1 - c^2*x^2)^p], Subst[Int[x^n*Sin[-a/b + x/b]^m*Cos[-a/b + x/b]^(2*p + 1), x],
 x, a + b*ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && IGtQ[2*p + 2, 0] && IGtQ[m,
 0]

Rubi steps \begin{align*} \text {integral}& = -\frac {\left (d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int x^n \cos ^4\left (\frac {a}{b}-\frac {x}{b}\right ) \sin \left (\frac {a}{b}-\frac {x}{b}\right ) \, dx,x,a+b \arcsin (c x)\right )}{b c^2 \sqrt {1-c^2 x^2}} \\ & = -\frac {\left (d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int \left (\frac {1}{16} x^n \sin \left (\frac {5 a}{b}-\frac {5 x}{b}\right )+\frac {3}{16} x^n \sin \left (\frac {3 a}{b}-\frac {3 x}{b}\right )+\frac {1}{8} x^n \sin \left (\frac {a}{b}-\frac {x}{b}\right )\right ) \, dx,x,a+b \arcsin (c x)\right )}{b c^2 \sqrt {1-c^2 x^2}} \\ & = -\frac {\left (d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int x^n \sin \left (\frac {5 a}{b}-\frac {5 x}{b}\right ) \, dx,x,a+b \arcsin (c x)\right )}{16 b c^2 \sqrt {1-c^2 x^2}}-\frac {\left (d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int x^n \sin \left (\frac {a}{b}-\frac {x}{b}\right ) \, dx,x,a+b \arcsin (c x)\right )}{8 b c^2 \sqrt {1-c^2 x^2}}-\frac {\left (3 d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int x^n \sin \left (\frac {3 a}{b}-\frac {3 x}{b}\right ) \, dx,x,a+b \arcsin (c x)\right )}{16 b c^2 \sqrt {1-c^2 x^2}} \\ & = -\frac {\left (i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-i \left (\frac {5 a}{b}-\frac {5 x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{32 b c^2 \sqrt {1-c^2 x^2}}+\frac {\left (i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{i \left (\frac {5 a}{b}-\frac {5 x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{32 b c^2 \sqrt {1-c^2 x^2}}-\frac {\left (i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-i \left (\frac {a}{b}-\frac {x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{16 b c^2 \sqrt {1-c^2 x^2}}+\frac {\left (i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{i \left (\frac {a}{b}-\frac {x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{16 b c^2 \sqrt {1-c^2 x^2}}-\frac {\left (3 i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-i \left (\frac {3 a}{b}-\frac {3 x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{32 b c^2 \sqrt {1-c^2 x^2}}+\frac {\left (3 i d \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{i \left (\frac {3 a}{b}-\frac {3 x}{b}\right )} x^n \, dx,x,a+b \arcsin (c x)\right )}{32 b c^2 \sqrt {1-c^2 x^2}} \\ & = -\frac {d e^{-\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {d e^{\frac {i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c x))}{b}\right )}{16 c^2 \sqrt {1-c^2 x^2}}-\frac {3^{-n} d e^{-\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {3^{-n} d e^{\frac {3 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {3 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {5^{-1-n} d e^{-\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (-\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}}-\frac {5^{-1-n} d e^{\frac {5 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {5 i (a+b \arcsin (c x))}{b}\right )}{32 c^2 \sqrt {1-c^2 x^2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 1.55 (sec) , antiderivative size = 464, normalized size of antiderivative = 0.78 \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=-\frac {15^{-1-n} d^2 e^{-\frac {5 i a}{b}} \sqrt {1-c^2 x^2} (a+b \arcsin (c x))^n \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^{-3 n} \left (2\ 15^{1+n} e^{\frac {4 i a}{b}} \left (\frac {i (a+b \arcsin (c x))}{b}\right )^n \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^{2 n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c x))}{b}\right )+\left (-\frac {i (a+b \arcsin (c x))}{b}\right )^n \left (2\ 15^{1+n} e^{\frac {6 i a}{b}} \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^{2 n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c x))}{b}\right )+3 \left (5^{1+n} e^{\frac {2 i a}{b}} \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{2 n} \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^n \Gamma \left (1+n,-\frac {3 i (a+b \arcsin (c x))}{b}\right )+5^{1+n} e^{\frac {8 i a}{b}} \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^{2 n} \Gamma \left (1+n,\frac {3 i (a+b \arcsin (c x))}{b}\right )+3^n \left (\left (-\frac {i (a+b \arcsin (c x))}{b}\right )^n \left (\frac {i (a+b \arcsin (c x))}{b}\right )^{3 n} \Gamma \left (1+n,-\frac {5 i (a+b \arcsin (c x))}{b}\right )+e^{\frac {10 i a}{b}} \left (\frac {(a+b \arcsin (c x))^2}{b^2}\right )^{2 n} \Gamma \left (1+n,\frac {5 i (a+b \arcsin (c x))}{b}\right )\right )\right )\right )\right )}{32 c^2 \sqrt {d-c^2 d x^2}} \]

[In]

Integrate[x*(d - c^2*d*x^2)^(3/2)*(a + b*ArcSin[c*x])^n,x]

[Out]

-1/32*(15^(-1 - n)*d^2*Sqrt[1 - c^2*x^2]*(a + b*ArcSin[c*x])^n*(2*15^(1 + n)*E^(((4*I)*a)/b)*((I*(a + b*ArcSin
[c*x]))/b)^n*((a + b*ArcSin[c*x])^2/b^2)^(2*n)*Gamma[1 + n, ((-I)*(a + b*ArcSin[c*x]))/b] + (((-I)*(a + b*ArcS
in[c*x]))/b)^n*(2*15^(1 + n)*E^(((6*I)*a)/b)*((a + b*ArcSin[c*x])^2/b^2)^(2*n)*Gamma[1 + n, (I*(a + b*ArcSin[c
*x]))/b] + 3*(5^(1 + n)*E^(((2*I)*a)/b)*((I*(a + b*ArcSin[c*x]))/b)^(2*n)*((a + b*ArcSin[c*x])^2/b^2)^n*Gamma[
1 + n, ((-3*I)*(a + b*ArcSin[c*x]))/b] + 5^(1 + n)*E^(((8*I)*a)/b)*((a + b*ArcSin[c*x])^2/b^2)^(2*n)*Gamma[1 +
 n, ((3*I)*(a + b*ArcSin[c*x]))/b] + 3^n*((((-I)*(a + b*ArcSin[c*x]))/b)^n*((I*(a + b*ArcSin[c*x]))/b)^(3*n)*G
amma[1 + n, ((-5*I)*(a + b*ArcSin[c*x]))/b] + E^(((10*I)*a)/b)*((a + b*ArcSin[c*x])^2/b^2)^(2*n)*Gamma[1 + n,
((5*I)*(a + b*ArcSin[c*x]))/b])))))/(c^2*E^(((5*I)*a)/b)*Sqrt[d - c^2*d*x^2]*((a + b*ArcSin[c*x])^2/b^2)^(3*n)
)

Maple [F]

\[\int x \left (-c^{2} d \,x^{2}+d \right )^{\frac {3}{2}} \left (a +b \arcsin \left (c x \right )\right )^{n}d x\]

[In]

int(x*(-c^2*d*x^2+d)^(3/2)*(a+b*arcsin(c*x))^n,x)

[Out]

int(x*(-c^2*d*x^2+d)^(3/2)*(a+b*arcsin(c*x))^n,x)

Fricas [F]

\[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=\int { {\left (-c^{2} d x^{2} + d\right )}^{\frac {3}{2}} {\left (b \arcsin \left (c x\right ) + a\right )}^{n} x \,d x } \]

[In]

integrate(x*(-c^2*d*x^2+d)^(3/2)*(a+b*arcsin(c*x))^n,x, algorithm="fricas")

[Out]

integral(-(c^2*d*x^3 - d*x)*sqrt(-c^2*d*x^2 + d)*(b*arcsin(c*x) + a)^n, x)

Sympy [F(-1)]

Timed out. \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=\text {Timed out} \]

[In]

integrate(x*(-c**2*d*x**2+d)**(3/2)*(a+b*asin(c*x))**n,x)

[Out]

Timed out

Maxima [F]

\[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=\int { {\left (-c^{2} d x^{2} + d\right )}^{\frac {3}{2}} {\left (b \arcsin \left (c x\right ) + a\right )}^{n} x \,d x } \]

[In]

integrate(x*(-c^2*d*x^2+d)^(3/2)*(a+b*arcsin(c*x))^n,x, algorithm="maxima")

[Out]

integrate((-c^2*d*x^2 + d)^(3/2)*(b*arcsin(c*x) + a)^n*x, x)

Giac [F(-2)]

Exception generated. \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=\text {Exception raised: TypeError} \]

[In]

integrate(x*(-c^2*d*x^2+d)^(3/2)*(a+b*arcsin(c*x))^n,x, algorithm="giac")

[Out]

Exception raised: TypeError >> an error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

Mupad [F(-1)]

Timed out. \[ \int x \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^n \, dx=\int x\,{\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^n\,{\left (d-c^2\,d\,x^2\right )}^{3/2} \,d x \]

[In]

int(x*(a + b*asin(c*x))^n*(d - c^2*d*x^2)^(3/2),x)

[Out]

int(x*(a + b*asin(c*x))^n*(d - c^2*d*x^2)^(3/2), x)